本篇内容介绍了“java List中如何筛选list中相同的值和筛选不同的值”的有关知识,在实际案例的操作过程中,不少人都会遇到这样的困境,接下来就让小编带领大家学习一下如何处理这些情况吧!希望大家仔细阅读,能够学有所成!
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public class People { private String id; private String somethingElse; public People() { } public People(String id, String somethingElse) { this.id = id; this.somethingElse = somethingElse; } public String getId() { return id; } public void setId(String id) { this.id = id; } public String getSomethingElse() { return somethingElse; } public void setSomethingElse(String somethingElse) { this.somethingElse = somethingElse; } @Override public String toString() { return "People{" + "id='" + id + '\'' + ", somethingElse='" + somethingElse + '\'' + '}'; } }
people实体类和student实体类
People类
student public class Student { private String id; private String idCard; private String somethingElse; public Student() { } public Student(String id, String idCard, String somethingElse) { this.id = id; this.idCard = idCard; this.somethingElse = somethingElse; } public String getId() { return id; } public void setId(String id) { this.id = id; } public String getIdCard() { return idCard; } public void setIdCard(String idCard) { this.idCard = idCard; } public String getSomethingElse() { return somethingElse; } public void setSomethingElse(String somethingElse) { this.somethingElse = somethingElse; } @Override public String toString() { return "Student{" + "id='" + id + '\'' + ", idCard='" + idCard + '\'' + ", somethingElse='" + somethingElse + '\'' + '}'; } }
测试类
public static void main(String[] args) throws Exception{ //初始化数据 List<Student> studentList = new ArrayList(){{ add(new Student("1", "11", "111")) ; add(new Student("2", "22", "222")); add(new Student("3", "33", "333")); }}; List<People> peopleList = new ArrayList(){ { add(new People("11", "111")); add(new People("222", "222")); add(new People("33", "333")); }}; //获取相同字段内容,转化为set Set<String> ids = peopleList .stream() .map(People::getId) .collect(Collectors.toSet());//过滤重复内容 List<Student> result = studentList .stream() .filter(e -> ids.contains(e.getIdCard())) .collect(Collectors.toList()); System.out.println(result); //获取相同字段内容,转化为set Set<String> ids = peopleList .stream() .map(People::getId) .collect(Collectors.toSet());//过滤重复内容 List<Student> result = studentList .stream() .filter(e -> !ids.contains(e.getIdCard())) .collect(Collectors.toList()); System.out.println(result); }
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